QWaitCondition¶

The QWaitCondition class provides a condition variable for synchronizing threads. More…

Synopsis¶

Functions¶

def notify_all ()
def notify_one ()
def wait (lockedMutex, time)
def wait (lockedMutex[, deadline=QDeadlineTimer(QDeadlineTimer.Forever)])
def wait (lockedReadWriteLock, time)
def wait (lockedReadWriteLock[, deadline=QDeadlineTimer(QDeadlineTimer.Forever)])
def wakeAll ()
def wakeOne ()

Detailed Description¶

QWaitCondition allows a thread to tell other threads that some sort of condition has been met. One or many threads can block waiting for a QWaitCondition to set a condition with wakeOne() or wakeAll() . Use wakeOne() to wake one randomly selected thread or wakeAll() to wake them all.

For example, let’s suppose that we have three tasks that should be performed whenever the user presses a key. Each task could be split into a thread, each of which would have a run() body like this:
while True:
    mutex.lock()
    keyPressed.wait(mutex)
    do_something()
    mutex.unlock()
Here, the keyPressed variable is a global variable of type QWaitCondition .

A fourth thread would read key presses and wake the other three threads up every time it receives one, like this:
while True:
    getchar()
    keyPressed.wakeAll()
The order in which the three threads are woken up is undefined. Also, if some of the threads are still in do_something() when the key is pressed, they won’t be woken up (since they’re not waiting on the condition variable) and so the task will not be performed for that key press. This issue can be solved using a counter and a QMutex to guard it. For example, here’s the new code for the worker threads:
while True:
    mutex.lock()
    keyPressed.wait(&mutex)
    count += 1
    mutex.unlock()

    do_something()

    mutex.lock()
    count -= 1
    mutex.unlock()
Here’s the code for the fourth thread:
while True:
    getchar()

    mutex.lock()
    # Sleep until there are no busy worker threads
    while count > 0:
        mutex.unlock()
        sleep(1)
        mutex.lock()
    keyPressed.wakeAll()
    mutex.unlock()
The mutex is necessary because the results of two threads attempting to change the value of the same variable simultaneously are unpredictable.

Wait conditions are a powerful thread synchronization primitive. The Wait Conditions Example example shows how to use QWaitCondition as an alternative to QSemaphore for controlling access to a circular buffer shared by a producer thread and a consumer thread.

See also

QMutex QSemaphore QThread Wait Conditions Example

class PySide2.QtCore.QWaitCondition¶: Constructs a new wait condition object.

PySide2.QtCore.QWaitCondition.notify_all()¶: This function is provided for STL compatibility. It is equivalent to wakeAll() .

PySide2.QtCore.QWaitCondition.notify_one()¶: This function is provided for STL compatibility. It is equivalent to wakeOne() .

PySide2.QtCore.QWaitCondition.wait(lockedMutex[, deadline=QDeadlineTimer(QDeadlineTimer.Forever)])¶

Parameters:

lockedMutex – PySide2.QtCore.QMutex
deadline – PySide2.QtCore.QDeadlineTimer

Return type:

bool

Releases the lockedMutex and waits on the wait condition. The lockedMutex must be initially locked by the calling thread. If lockedMutex is not in a locked state, the behavior is undefined. If lockedMutex is a recursive mutex, this function returns immediately. The lockedMutex will be unlocked, and the calling thread will block until either of these conditions is met:

Another thread signals it using wakeOne() or wakeAll() . This function will return true in this case.
the deadline given by deadline is reached. If deadline is QDeadlineTimer::Forever (the default), then the wait will never timeout (the event must be signalled). This function will return false if the wait timed out.

The lockedMutex will be returned to the same locked state. This function is provided to allow the atomic transition from the locked state to the wait state.

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QWaitCondition¶

Synopsis¶

Functions¶

Detailed Description¶