CertC-INT32¶
Ensure that operations on signed integers do not result in overflow
Required inputs: IR, StaticSemanticAnalysis
Signed integer overflow is undefined behavior 36. Consequently, implementations have considerable latitude in how they deal with signed integer overflow. (See MSC15-C. Do not depend on undefined behavior.) An implementation that defines signed integer types as being modulo, for example, need not detect integer overflow. Implementations may also trap on signed arithmetic overflows, or simply assume that overflows will never happen and generate object code accordingly. It is also possible for the same conforming implementation to emit code that exhibits different behavior in different contexts. For example, an implementation may determine that a signed integer loop control variable declared in a local scope cannot overflow and may emit efficient code on the basis of that determination, while the same implementation may determine that a global variable used in a similar context will wrap.
For these reasons, it is important to ensure that operations on signed integers do not result in overflow. Of particular importance are operations on signed integer values that originate from a tainted source and are used as
- Integer operands of any pointer arithmetic, including array indexing
- The assignment expression for the declaration of a variable length array
- The postfix expression preceding square brackets
[]or the expression in square brackets[]of a subscripted designation of an element of an array object - Function arguments of type
size_torrsize_t(for example, an argument to a memory allocation function)
Integer operations will overflow if the resulting value cannot be represented by the underlying representation of the integer. The following table indicates which operations can result in overflow.
| Operator | Overflow | Operator | Overflow | Operator | Overflow | Operator | Overflow |
|---|---|---|---|---|---|---|---|
+ |
Yes | -= |
Yes | << |
Yes | < |
No |
- |
Yes | *= |
Yes | >> |
No | > |
No |
* |
Yes | /= |
Yes | & |
No | >= |
No |
/ |
Yes | %= |
Yes | | |
No | <= |
No |
% |
Yes | <<= |
Yes | ^ |
No | == |
No |
++ |
Yes | >>= |
No | ~ |
No | != |
No |
-- |
Yes | &= |
No | ! |
No | && |
No |
= |
No | |= |
No | unary + |
No | || |
No |
+= |
Yes | ^= |
No | unary - |
Yes | ?: |
No |
The following sections examine specific operations that are susceptible to
integer overflow. When operating on integer types with less precision than
int, integer promotions are applied. The usual arithmetic
conversions may also be applied to (implicitly) convert operands to equivalent
types before arithmetic operations are performed. Programmers should understand
integer conversion rules before trying to implement secure arithmetic
operations. (See
INT02-C.
Understand integer conversion rules.)
Implementation Details
GNU GCC invoked with the
-fwrapv command-line option defines the same modulo
arithmetic for both unsigned and signed integers.
GNU GCC invoked with the
-ftrapv command-line option causes a trap to be
generated when a signed integer overflows, which will most likely abnormally
exit. On a UNIX system, the result of such an event may be a signal sent to the
process.
GNU GCC invoked without either the
-fwrapv or the
-ftrapv option may simply assume that signed integers never
overflow and may generate object code accordingly.
Atomic Integers
The C Standard defines the behavior of arithmetic on atomic signed integer types to use two's complement representation with silent wraparound on overflow; there are no undefined results. Although defined, these results may be unexpected and therefore carry similar risks to unsigned integer wrapping. (See INT30-C. Ensure that unsigned integer operations do not wrap.) Consequently, signed integer overflow of atomic integer types should also be prevented or detected.
Addition
Addition is between two operands of arithmetic type or between a pointer to an object type and an integer type. This rule applies only to addition between two operands of arithmetic type. (See ARR37-C. Do not add or subtract an integer to a pointer to a non-array object and ARR30-C. Do not form or use out-of-bounds pointers or array subscripts.)
Incrementing is equivalent to adding 1.
Noncompliant Code Example
This noncompliant code example can result in a signed integer overflow during
the addition of the signed operands
si_a and
si_b:
void func(signed int si_a, signed int si_b) {
signed int sum = si_a + si_b;
/* ... */
}
Compliant Solution
This compliant solution ensures that the addition operation cannot overflow, regardless of representation:
#include <limits.h>
void f(signed int si_a, signed int si_b) {
signed int sum;
if (((si_b > 0) && (si_a > (INT_MAX - si_b))) ||
((si_b < 0) && (si_a < (INT_MIN - si_b)))) {
/* Handle error */
} else {
sum = si_a + si_b;
}
/* ... */
}
Compliant Solution (GNU)
This compliant solution uses the GNU extension
__builtin_sadd_overflow, available with GCC, Clang, and ICC:
void f(signed int si_a, signed int si_b) {
signed int sum;
if (__builtin_sadd_overflow(si_a, si_b, &sum)) {
/* Handle error */
}
/* ... */
}
Subtraction
Subtraction is between two operands of arithmetic type, two pointers to qualified or unqualified versions of compatible object types, or a pointer to an object type and an integer type. This rule applies only to subtraction between two operands of arithmetic type. (See ARR36-C. Do not subtract or compare two pointers that do not refer to the same array, ARR37-C. Do not add or subtract an integer to a pointer to a non-array object, and ARR30-C. Do not form or use out-of-bounds pointers or array subscripts for information about pointer subtraction.)
Decrementing is equivalent to subtracting 1.
Noncompliant Code Example
This noncompliant code example can result in a signed integer overflow during
the subtraction of the signed operands
si_a and
si_b:
void func(signed int si_a, signed int si_b) {
signed int diff = si_a - si_b;
/* ... */
}
Compliant Solution
This compliant solution tests the operands of the subtraction to guarantee there is no possibility of signed overflow, regardless of representation:
#include <limits.h>
void func(signed int si_a, signed int si_b) {
signed int diff;
if ((si_b > 0 && si_a < INT_MIN + si_b) ||
(si_b < 0 && si_a > INT_MAX + si_b)) {
/* Handle error */
} else {
diff = si_a - si_b;
}
/* ... */
}
Compliant Solution (GNU)
This compliant solution uses the GNU extension
__builtin_ssub_overflow, available with GCC, Clang, and ICC:
void func(signed int si_a, signed int si_b) {
signed int diff;
if (__builtin_ssub_overflow(si_a, si_b, &diff)) {
/* Handle error */
}
/* ... */
}
Multiplication
Multiplication is between two operands of arithmetic type.
Noncompliant Code Example
This noncompliant code example can result in a signed integer overflow during
the multiplication of the signed operands
si_a and
si_b:
void func(signed int si_a, signed int si_b) {
signed int result = si_a * si_b;
/* ... */
}
Compliant Solution
The product of two operands can always be represented using twice the number of
bits than exist in the precision of the larger of the two operands. This
compliant solution eliminates signed overflow on systems where
long long is at least twice the precision of
int:
#include <stddef.h>
#include <assert.h>
#include <limits.h>
#include <inttypes.h>
extern size_t popcount(uintmax_t);
#define PRECISION(umax_value) popcount(umax_value)
void func(signed int si_a, signed int si_b) {
signed int result;
signed long long tmp;
assert(PRECISION(ULLONG_MAX) >= 2 * PRECISION(UINT_MAX));
tmp = (signed long long)si_a * (signed long long)si_b;
/*
* If the product cannot be represented as a 32-bit integer,
* handle as an error condition.
*/
if ((tmp > INT_MAX) || (tmp < INT_MIN)) {
/* Handle error */
} else {
result = (int)tmp;
}
/* ... */
}
The assertion fails if
long long has less than twice the precision of
int. The
PRECISION() macro and
popcount() function provide the correct precision for any
integer type. (See
INT35-C.
Use correct integer precisions.)
Compliant Solution
The following portable compliant solution can be used with any conforming
implementation, including those that do not have an integer type that is at
least twice the precision of
int:
#include <limits.h>
void func(signed int si_a, signed int si_b) {
signed int result;
if (si_a > 0) { /* si_a is positive */
if (si_b > 0) { /* si_a and si_b are positive */
if (si_a > (INT_MAX / si_b)) {
/* Handle error */
}
} else { /* si_a positive, si_b nonpositive */
if (si_b < (INT_MIN / si_a)) {
/* Handle error */
}
} /* si_a positive, si_b nonpositive */
} else { /* si_a is nonpositive */
if (si_b > 0) { /* si_a is nonpositive, si_b is positive */
if (si_a < (INT_MIN / si_b)) {
/* Handle error */
}
} else { /* si_a and si_b are nonpositive */
if ( (si_a != 0) && (si_b < (INT_MAX / si_a))) {
/* Handle error */
}
} /* End if si_a and si_b are nonpositive */
} /* End if si_a is nonpositive */
result = si_a * si_b;
}
Compliant Solution (GNU)
This compliant solution uses the GNU extension
__builtin_smul_overflow, available with GCC, Clang, and ICC:
void func(signed int si_a, signed int si_b) {
signed int result;
if (__builtin_smul_overflow(si_a, si_b, &result)) {
/* Handle error */
}
}
Division
Division is between two operands of arithmetic type. Overflow can occur during
two's complement signed integer division when the dividend is equal to the
minimum (negative) value for the signed integer type and the divisor is equal
to
-1. Division operations are also susceptible to divide-by-zero
errors. (See
INT33-C.
Ensure that division and remainder operations do not result in divide-by-zero
errors.)
Noncompliant Code Example
This noncompliant code example prevents divide-by-zero errors in compliance with INT33-C. Ensure that division and remainder operations do not result in divide-by-zero errors but does not prevent a signed integer overflow error in two's-complement.
void func(signed long s_a, signed long s_b) {
signed long result;
if (s_b == 0) {
/* Handle error */
} else {
result = s_a / s_b;
}
/* ... */
}
Implementation Details
On the x86-32 architecture, overflow results in a fault, which can be exploited as a denial-of-service attack.
Compliant Solution
This compliant solution eliminates the possibility of divide-by-zero errors or signed overflow:
#include <limits.h>
void func(signed long s_a, signed long s_b) {
signed long result;
if ((s_b == 0) || ((s_a == LONG_MIN) && (s_b == -1))) {
/* Handle error */
} else {
result = s_a / s_b;
}
/* ... */
}
Remainder
The remainder operator provides the remainder when two operands of integer type are divided. Because many platforms implement remainder and division in the same instruction, the remainder operator is also susceptible to arithmetic overflow and division by zero. (See INT33-C. Ensure that division and remainder operations do not result in divide-by-zero errors.)
Noncompliant Code Example
Many hardware architectures implement remainder as part of the division operator, which can overflow. Overflow can occur during a remainder operation when the dividend is equal to the minimum (negative) value for the signed integer type and the divisor is equal to -1. It occurs even though the result of such a remainder operation is mathematically 0. This noncompliant code example prevents divide-by-zero errors in compliance with INT33-C. Ensure that division and remainder operations do not result in divide-by-zero errors but does not prevent integer overflow:
void func(signed long s_a, signed long s_b) {
signed long result;
if (s_b == 0) {
/* Handle error */
} else {
result = s_a % s_b;
}
/* ... */
}
Implementation Details
On x86-32 platforms, the remainder operator for signed integers is implemented
by the
idiv instruction code, along with the divide operator.
Because
LONG_MIN / -1 overflows, it results in a software exception
with
LONG_MIN % -1 as well.
Compliant Solution
This compliant solution also tests the remainder operands to guarantee there is no possibility of an overflow:
#include <limits.h>
void func(signed long s_a, signed long s_b) {
signed long result;
if ((s_b == 0 ) || ((s_a == LONG_MIN) && (s_b == -1))) {
/* Handle error */
} else {
result = s_a % s_b;
}
/* ... */
}
Left-Shift Operator
The left-shift operator takes two integer operands. The result of
E1 << E2 is
E1 left-shifted
E2 bit positions; vacated bits are filled with zeros.
The C Standard, 6.5.7, paragraph 4 [ ISO/IEC 9899:2011], states
If
E1has a signed type and nonnegative value, andE1 × 2E2is representable in the result type, then that is the resulting value; otherwise, the behavior is undefined.
In almost every case, an attempt to shift by a negative number of bits or by more bits than exist in the operand indicates a logic error. These issues are covered by INT34-C. Do not shift an expression by a negative number of bits or by greater than or equal to the number of bits that exist in the operand.
Noncompliant Code Example
This noncompliant code example performs a left shift, after verifying that the
number being shifted is not negative, and the number of bits to shift is valid.
The
PRECISION() macro and
popcount() function provide the correct precision for any
integer type. (See
INT35-C.
Use correct integer precisions.) However, because this code does no
overflow check, it can result in an unrepresentable value.
#include <limits.h>
#include <stddef.h>
#include <inttypes.h>
extern size_t popcount(uintmax_t);
#define PRECISION(umax_value) popcount(umax_value)
void func(signed long si_a, signed long si_b) {
signed long result;
if ((si_a < 0) || (si_b < 0) ||
(si_b >= PRECISION(ULONG_MAX)) {
/* Handle error */
} else {
result = si_a << si_b;
}
/* ... */
}
Compliant Solution
This compliant solution eliminates the possibility of overflow resulting from a left-shift operation:
#include <limits.h>
#include <stddef.h>
#include <inttypes.h>
extern size_t popcount(uintmax_t);
#define PRECISION(umax_value) popcount(umax_value)
void func(signed long si_a, signed long si_b) {
signed long result;
if ((si_a < 0) || (si_b < 0) ||
(si_b >= PRECISION(ULONG_MAX)) ||
(si_a > (LONG_MAX >> si_b))) {
/* Handle error */
} else {
result = si_a << si_b;
}
/* ... */
}
Unary Negation
The unary negation operator takes an operand of arithmetic type. Overflow can occur during two's complement unary negation when the operand is equal to the minimum (negative) value for the signed integer type.
Noncompliant Code Example
This noncompliant code example can result in a signed integer overflow during
the unary negation of the signed operand
s_a:
void func(signed long s_a) {
signed long result = -s_a;
/* ... */
}
Compliant Solution
This compliant solution tests the negation operation to guarantee there is no possibility of signed overflow:
#include <limits.h>
void func(signed long s_a) {
signed long result;
if (s_a == LONG_MIN) {
/* Handle error */
} else {
result = -s_a;
}
/* ... */
}
Risk Assessment
Integer overflow can lead to buffer overflows and the execution of arbitrary code by an attacker.
| Rule | Severity | Likelihood | Remediation Cost | Priority | Level |
|---|---|---|---|---|---|
| INT32-C | High | Likely | High | P9 | L2 |
Related Guidelines
| Taxonomy | Taxonomy item | Relationship |
|---|---|---|
| CERT C | INT02-C. Understand integer conversion rules | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | INT35-C. Use correct integer precisions | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | INT33-C. Ensure that division and remainder operations do not result in divide-by-zero errors | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | INT34-C. Do not shift an expression by a negative number of bits or by greater than or equal to the number of bits that exist in the operand | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | ARR30-C. Do not form or use out-of-bounds pointers or array subscripts | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | ARR36-C. Do not subtract or compare two pointers that do not refer to the same array | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | ARR37-C. Do not add or subtract an integer to a pointer to a non-array object | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | MSC15-C. Do not depend on undefined behavior | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT C | CON08-C. Do not assume that a group of calls to independently atomic methods is atomic | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CERT Oracle Secure Coding Standard for Java | INT00-J. Perform explicit range checking to avoid integer overflow | Prior to 2018-01-12: CERT: Unspecified Relationship |
| ISO/IEC TR 24772:2013 | Arithmetic Wrap-Around Error [FIF] | Prior to 2018-01-12: CERT: Unspecified Relationship |
| ISO/IEC TS 17961 | Overflowing signed integers [intoflow] | Prior to 2018-01-12: CERT: Unspecified Relationship |
| CWE 2.11 | CWE-190, Integer Overflow or Wraparound | 2017-05-18: CERT: Partial overlap |
| CWE 2.11 | CWE-191 | 2017-05-18: CERT: Partial overlap |
| CWE 2.11 | CWE-680 | 2017-05-18: CERT: Partial overlap |
Bibliography
| [ Dowd 2006] | Chapter 6, "C Language Issues" ("Arithmetic Boundary Conditions," pp. 211-223) |
| [ ISO/IEC 9899:2011] | Subclause 6.5.5, "Multiplicative Operators" |
| [ Seacord 2013b] | Chapter 5, "Integer Security" |
| [ Viega 2005] | Section 5.2.7, "Integer Overflow" |
| [ Warren 2002] | Chapter 2, "Basics" |
Possible Messages
Key |
Text |
Severity |
Disabled |
|---|---|---|---|
certain_shift_amount_negative |
Shift by a negative bit count (undefined behavior) |
None |
False |
certain_shift_amount_too_large |
Shift by the integer width or more (undefined behavior) |
None |
False |
certain_shift_right_negative |
Right shift with negative left-hand-side |
None |
False |
overflow |
Arithmetic computation may cause overflow |
None |
False |
underflow |
Arithmetic computation may cause overflow |
None |
False |
Options¶
This rule shares the following common options: exclude_in_macros, exclude_messages_in_system_headers, excludes, extend_exclude_to_macro_invocations, includes, justification_checker, languages, post_processing, provider, report_at, severity
The following places define options that affect this rule: Stylechecks, Analysis-GlobalOptions
abstract_interpretation_maximal_tracked_array_index¶
abstract_interpretation_maximal_tracked_array_index : int = 10
The number of explicit indices in array expressions per routine tracked by the "symbolic expression analysis". For example, consider the following program.
extern signed char a[6];
int main()
{
if (a[2] < 0)
{
a[2]++;
}
if (a[3] < 0)
{
a[3]++;
}
if (a[4] < 0)
{
a[4]++;
}
return 0;
}
If the value of this option is set to 2, the first two array index expressions
encountered in the routine are tracked. Hence, the analysis can use the facts
a[2] < 0 and a[3] < 0 to infer that a[2]++
and a[3]++ do not overflow, but it will not track the third array
access in this routine.
A higher value of the option can cause more consumption of memory and time for the analysis.
abstract_interpretation_overflow¶
abstract_interpretation_overflow : bool = True
abstract_interpretation_overflow_unrolling_level¶
abstract_interpretation_overflow_unrolling_level : int = 0
check_signed¶
check_signed : bool = True
check_unsigned¶
check_unsigned : bool = False
suppress_well_defined_findings¶
suppress_well_defined_findings : SuppressionMode = 'NONE'
Some overflows have well-defined semantics in all C/C++ standard
versions. The typical example is UINT_MAX+1 which is
well-defined as 0 via wraparound. This differs from
INT_MAX+1 which is either undefined or implementation-defined
depending on the considered standard version. Most CPUs will compute
INT_MIN but this wraparound is not guaranteed by any C/C++
standard.
Both cases are overflows and are reported by this rule. However, one might want to suppress messages for the well-defined cases. To suppress these activate this option.
Different C and C++ standard versions differ in what is well-defined, implementation-defined, or undefined. Luckily, if we only consider well-defined and do not discern between implementation-defined and undefined, we end up with only two groups: pre-C++20 and since-C++20.
Option Types¶
These types are used by options listed above:
SuppressionMode¶
An enumeration.NONE
Suppress nothing.
PRE_CPP2020
Suppress findings that are well-defined before C++20. These are:
- Over- and underflows of unsigned integers during addition, subtraction, and multiplication
- Conversions from unsigned to unsigned integers
- Wrap-around caused by left-shifting of unsigned integer
CPP2020
Suppress findings that are well-defined since C++20. These are:
- Over- and underflows of unsigned integers during addition, subtraction, and multiplication
- Conversions between signed and unsigned integers
- Wrap-around caused by left-shifting
- Shifting negative integers
Surprising mechanics of C++20 signed narrow integers
Since C++20, casts between signed and unsigned are defined as two-complement wrap-around. Overflows of signed integers are still undefined behavior and are reported by this rule. But, due to integer promotion rules, certain expressions are computed using wider integer types, which can lead to the false impression that this is no longer the case, because no overflow findings are reported there.
Suppose, that the code is compiled on a platform where short
is smaller than or equal to half the size of an int. Very
commonly the sizes are 2 and 4. This assumption is thus true for many
platforms.
In this case, narrow signed integer types such as short or
signed char are first implicitly promoted to int
before the arithmetic operation is executed. Because of this promotion, the
actual operation does not overflow and is thus well-defined. After the
operation, an implicit cast is performed to the narrower type. This cast is
well-defined in C++20 as wrapping around.
Consider the following snippet:
static_assert(sizeof(short) == 2);
static_assert(sizeof(int) == 4);
short a = 0x1000;
short b = 0x1001;
short c = a*b;
C++20 defines c as 0x1000. The reason is that
a*b is implicitly promoted to static_cast<int>
(a)*static_cast<int>(b). After the promotion, the
multiplication does not overflow and yields a well-defined
0x1001000. This number is then implicitly cast to
0x1000 which is also a well-defined operation.
An analogous effect can be observed for signed short addition and
multiplication. Another effect is that it is well-defined to shift by up to
as many bits as int has even if the shifted integer has fewer
bits.
DERIVE_FROM_IR
Derive the language version from the IR compilation flags and suppress findings accordingly.