Obsolete Members for QtFuture
The following members of class QtFuture are deprecated. They are provided to keep old source code working. We strongly advise against using them in new code.
Functions
(deprecated (6.10)) QFuture<std::decay_t<T>> | makeReadyFuture(T &&value) |
(deprecated (6.10)) QFuture<T> | makeReadyFuture(const QList<T> &values) |
(deprecated (6.10)) QFuture<void> | makeReadyFuture() |
Function Documentation
[since 6.1]
template <typename T, typename> QFuture<std::decay_t<T>> QtFuture::makeReadyFuture(T &&value)
This function is deprecated since 6.10. We strongly advise against using it in new code.
This is an overloaded function.
Use makeReadyValueFuture() instead
The QtFuture::makeReadyFuture() method should be avoided because it has an inconsistent set of overloads. It will be deprecated in future Qt releases. Use QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture() or QtFuture::makeReadyRangeFuture() instead.
Creates and returns a QFuture which already has a result value. The returned QFuture has a type of std::decay_t<T>, where T is not void.
auto f = QtFuture::makeReadyFuture(std::make_unique<int>(42)); ... const int result = *f.takeResult(); // result == 42
This function was introduced in Qt 6.1.
See also QFuture, QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture(), QtFuture::makeReadyRangeFuture(), and QtFuture::makeExceptionalFuture().
[since 6.1]
template <typename T> QFuture<T> QtFuture::makeReadyFuture(const QList<T> &values)
This function is deprecated since 6.10. We strongly advise against using it in new code.
This is an overloaded function.
Use makeReadyRangeFuture() instead
The QtFuture::makeReadyFuture() method should be avoided because it has an inconsistent set of overloads. It will be deprecated in future Qt releases. Use QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture() or QtFuture::makeReadyRangeFuture() instead.
Creates and returns a QFuture which already has multiple results set from values.
const QList<int> values { 1, 2, 3 }; auto f = QtFuture::makeReadyFuture(values); ... const int count = f.resultCount(); // count == 3 const auto results = f.results(); // results == { 1, 2, 3 }
This function was introduced in Qt 6.1.
See also QFuture, QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture(), QtFuture::makeReadyRangeFuture(), and QtFuture::makeExceptionalFuture().
[since 6.1]
QFuture<void> QtFuture::makeReadyFuture()
This function is deprecated since 6.10. We strongly advise against using it in new code.
This is an overloaded function.
Use makeReadyVoidFuture() instead
The QtFuture::makeReadyFuture() method should be avoided because it has an inconsistent set of overloads. It will be deprecated in future Qt releases. Use QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture() or QtFuture::makeReadyRangeFuture() instead.
Creates and returns a void QFuture. Such QFuture can't store any result. One can use it to query the state of the computation. The returned QFuture will always be in the finished state.
auto f = QtFuture::makeReadyFuture(); ... const bool started = f.isStarted(); // started == true const bool running = f.isRunning(); // running == false const bool finished = f.isFinished(); // finished == true
This function was introduced in Qt 6.1.
See also QFuture, QFuture::isStarted(), QFuture::isRunning(), QFuture::isFinished(), QtFuture::makeReadyVoidFuture(), QtFuture::makeReadyValueFuture(), QtFuture::makeReadyRangeFuture(), and QtFuture::makeExceptionalFuture().
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